30x+20(28-x)+15*(28-(x+(28-x)))=800 equation
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The solution
Detail solution
Given the linear equation:
30*x+20*(28-x)+15*(28-(x+(28-x))) = 800
Expand brackets in the left part
30*x+20*28-20*x+15*28+15*x+15*28-15*x)) = 800
Looking for similar summands in the left part:
560 + 10*x = 800
Move free summands (without x)
from left part to right part, we given:
$$10 x = 240$$
Divide both parts of the equation by 10
x = 240 / (10)
We get the answer: x = 24
Sum and product of roots
[src]
$$24$$
$$24$$
$$24$$
$$24$$