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30x+20(28-x)+15*(28-(x+(28-x)))=800 equation

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Numerical solution:

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The solution

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30*x + 20*(28 - x) + 15*(28 + -x + -28 + x) = 800
$$\left(30 x + 20 \left(28 - x\right)\right) + 15 \left(\left(- x + \left(x - 28\right)\right) + 28\right) = 800$$
Detail solution
Given the linear equation:
30*x+20*(28-x)+15*(28-(x+(28-x))) = 800

Expand brackets in the left part
30*x+20*28-20*x+15*28+15*x+15*28-15*x)) = 800

Looking for similar summands in the left part:
560 + 10*x = 800

Move free summands (without x)
from left part to right part, we given:
$$10 x = 240$$
Divide both parts of the equation by 10
x = 240 / (10)

We get the answer: x = 24
The graph
Rapid solution [src]
x1 = 24
$$x_{1} = 24$$
x1 = 24
Sum and product of roots [src]
sum
24
$$24$$
=
24
$$24$$
product
24
$$24$$
=
24
$$24$$
24
Numerical answer [src]
x1 = 24.0
x1 = 24.0