Mister Exam
Other calculators
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How to use it?
- Equation:
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Equation 2x^2-x=0
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Equation 4*x^2-13*x+3=0
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Equation -x^2+6*x-7=0
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Equation x(x^2+6x+9)=-2(x+3)
- Express {x} in terms of y where:
- -19*x-6*y=10
- 19*x-6*y=0
- 15*x+3*y=-16
- -4*x-3*y=-3
- 2x+2y+3
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Identical expressions
- 2x+2y+ three = nine
- 2x plus 2y plus 3 equally 9
- 2x plus 2y plus three equally nine
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Similar expressions
- 2x+2y-3=9
- 2x-2y+3=9
2x+2y+3=9 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Looking for similar summands in the left part:
Move free summands (without x)
from left part to right part, we given:
$$2 x + 2 y = 6$$
Move the summands with the other variables
from left part to right part, we given:
$$2 x = \left(-2\right) y + 6$$
Divide both parts of the equation by 2
We get the answer: x = 3 - y
2*x+2*y+3 = 9
Looking for similar summands in the left part:
3 + 2*x + 2*y = 9
Move free summands (without x)
from left part to right part, we given:
$$2 x + 2 y = 6$$
Move the summands with the other variables
from left part to right part, we given:
$$2 x = \left(-2\right) y + 6$$
Divide both parts of the equation by 2
x = 6 - 2*y / (2)
We get the answer: x = 3 - y
The graph
Rapid solution
[src]
x1 = 3 - re(y) - I*im(y)
$$x_{1} = - \operatorname{re}{\left(y\right)} - i \operatorname{im}{\left(y\right)} + 3$$
x1 = -re(y) - i*im(y) + 3
Sum and product of roots
[src]
sum
3 - re(y) - I*im(y)
$$- \operatorname{re}{\left(y\right)} - i \operatorname{im}{\left(y\right)} + 3$$
=
3 - re(y) - I*im(y)
$$- \operatorname{re}{\left(y\right)} - i \operatorname{im}{\left(y\right)} + 3$$
product
3 - re(y) - I*im(y)
$$- \operatorname{re}{\left(y\right)} - i \operatorname{im}{\left(y\right)} + 3$$
=
3 - re(y) - I*im(y)
$$- \operatorname{re}{\left(y\right)} - i \operatorname{im}{\left(y\right)} + 3$$
3 - re(y) - i*im(y)