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(2x-12)*(x+4)=0 equation

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Numerical solution:

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The solution

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(2*x - 12)*(x + 4) = 0
$$\left(x + 4\right) \left(2 x - 12\right) = 0$$
Detail solution
Expand the expression in the equation
$$\left(x + 4\right) \left(2 x - 12\right) = 0$$
We get the quadratic equation
$$2 x^{2} - 4 x - 48 = 0$$
This equation is of the form
a*x^2 + b*x + c = 0

A quadratic equation can be solved
using the discriminant.
The roots of the quadratic equation:
$$x_{1} = \frac{\sqrt{D} - b}{2 a}$$
$$x_{2} = \frac{- \sqrt{D} - b}{2 a}$$
where D = b^2 - 4*a*c - it is the discriminant.
Because
$$a = 2$$
$$b = -4$$
$$c = -48$$
, then
D = b^2 - 4 * a * c = 

(-4)^2 - 4 * (2) * (-48) = 400

Because D > 0, then the equation has two roots.
x1 = (-b + sqrt(D)) / (2*a)

x2 = (-b - sqrt(D)) / (2*a)

or
$$x_{1} = 6$$
$$x_{2} = -4$$
Sum and product of roots [src]
sum
-4 + 6
$$-4 + 6$$
=
2
$$2$$
product
-4*6
$$- 24$$
=
-24
$$-24$$
-24
Rapid solution [src]
x1 = -4
$$x_{1} = -4$$
x2 = 6
$$x_{2} = 6$$
x2 = 6
Numerical answer [src]
x1 = -4.0
x2 = 6.0
x2 = 6.0