Mister Exam
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How to use it?
- Equation:
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Equation (2-c)+3*(c-3)=-13
-
Equation 7(x-1)=3x
-
Equation 141*10^(-6)*x*3*sqrt(2)=sqrt((1-19881*10^(-12)*x^2)^2+9)
- Equation 7*x^3-63*x=0
- Express {x} in terms of y where:
- -20*x+6*y=-12
- -15*x+18*y=0
- 14*x+5*y=11
- -11*x-8*y=-14
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Identical expressions
- 2x- thirty-seven =7x- thirteen
- 2x minus 37 equally 7x minus 13
- 2x minus thirty minus seven equally 7x minus thirteen
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Similar expressions
- 2x+37=7x-13
- 19-2*(3*x+18*x)=2*x-37
- -5(-x+3)-12=7(x-13)+16
- 2x-37=7x+13
- -x^3+4*x^2+7*x-13=0
2x-37=7x-13 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Move free summands (without x)
from left part to right part, we given:
$$2 x = 7 x + 24$$
Move the summands with the unknown x
from the right part to the left part:
$$\left(-5\right) x = 24$$
Divide both parts of the equation by -5
We get the answer: x = -24/5
2*x-37 = 7*x-13
Move free summands (without x)
from left part to right part, we given:
$$2 x = 7 x + 24$$
Move the summands with the unknown x
from the right part to the left part:
$$\left(-5\right) x = 24$$
Divide both parts of the equation by -5
x = 24 / (-5)
We get the answer: x = -24/5
Sum and product of roots
[src]
sum
-24/5
$$- \frac{24}{5}$$
=
-24/5
$$- \frac{24}{5}$$
product
-24/5
$$- \frac{24}{5}$$
=
-24/5
$$- \frac{24}{5}$$
-24/5