Mister Exam
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How to use it?
- Equation:
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Equation x+7*4=40
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Equation 4*x^2-13*x+3=0
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Equation 3x+5=0
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Equation x^3-2x+1=0
- Express {x} in terms of y where:
- -3*x+1*y=5
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Identical expressions
- 2ctgt-t= zero
- 2ctgt minus t equally 0
- 2ctgt minus t equally zero
- 2ctgt-t=O
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Similar expressions
- 2ctgt+t=0
2ctgt-t=0 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the equation
$$- t + 2 \cot{\left(t \right)} = 0$$
transform
$$- t + 2 \cot{\left(t \right)} - 1 = 0$$
$$- t + 2 \cot{\left(t \right)} - 1 = 0$$
Do replacement
$$w = \cot{\left(t \right)}$$
Move free summands (without w)
from left part to right part, we given:
$$- t + 2 w = 1$$
Move the summands with the other variables
from left part to right part, we given:
$$2 w = t + 1$$
Divide both parts of the equation by 2
We get the answer: w = 1/2 + t/2
do backward replacement
$$\cot{\left(t \right)} = w$$
substitute w:
$$- t + 2 \cot{\left(t \right)} = 0$$
transform
$$- t + 2 \cot{\left(t \right)} - 1 = 0$$
$$- t + 2 \cot{\left(t \right)} - 1 = 0$$
Do replacement
$$w = \cot{\left(t \right)}$$
Move free summands (without w)
from left part to right part, we given:
$$- t + 2 w = 1$$
Move the summands with the other variables
from left part to right part, we given:
$$2 w = t + 1$$
Divide both parts of the equation by 2
w = 1 + t / (2)
We get the answer: w = 1/2 + t/2
do backward replacement
$$\cot{\left(t \right)} = w$$
substitute w:
Numerical answer
[src]
t1 = 12.7222987717666
t2 = 3.6435971674254
t3 = -15.8336114149477
t4 = -9.62956034329743
t5 = -37.7520396346102
t6 = 1.0768739863118
t7 = 9.62956034329743
t8 = -3.6435971674254
t9 = -1.0768739863118
t9 = -1.0768739863118