Mister Exam
Other calculators
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How to use it?
- Equation:
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Equation 2*x^2+6*x+9=0
-
Equation cos(x)=(1/2)
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Equation (x^2-4)^2+(x^2-6*x-16)^2=0
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Equation 3x^2-5x-2=0
- Express {x} in terms of y where:
- 17*x-18*y=10
- 9*x-4*y=2
- -16*x-20*y=6
- 20*x+6*y=8
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Identical expressions
- 1 seven x- eight =20x-7
- 17x minus 8 equally 20x minus 7
- 1 seven x minus eight equally 20x minus 7
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Similar expressions
- 17x-8=20x+7
- 17x+8=20x-7
- 20*x-7-3*x^2+(5+x)^2=0
- 0,002*x^2+20*x-75000=0
- 2*x^2-20*x-72=0
- 17*x-8=20*x+7
- x^3+7*x^2-20*x-72=0
17x-8=20x-7 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Move free summands (without x)
from left part to right part, we given:
$$17 x = 20 x + 1$$
Move the summands with the unknown x
from the right part to the left part:
$$- 3 x = 1$$
Divide both parts of the equation by -3
We get the answer: x = -1/3
17*x-8 = 20*x-7
Move free summands (without x)
from left part to right part, we given:
$$17 x = 20 x + 1$$
Move the summands with the unknown x
from the right part to the left part:
$$- 3 x = 1$$
Divide both parts of the equation by -3
x = 1 / (-3)
We get the answer: x = -1/3
Sum and product of roots
[src]
sum
0 - 1/3
$$- \frac{1}{3} + 0$$
=
-1/3
$$- \frac{1}{3}$$
product
1*-1/3
$$1 \left(- \frac{1}{3}\right)$$
=
-1/3
$$- \frac{1}{3}$$
-1/3
The graph