Mister Exam
Other calculators
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How to use it?
- Equation:
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Equation x^2-8=(x-4)^2
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Equation 36-x^2=0
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Equation 4-x=1
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Equation (2-c)+3(c-3)=-13
- Express {x} in terms of y where:
- 8*x+5*y=-12
- -7*x-4*y=-4
- -2*x-10*y=20
- -1*x+11*y=16
- Sum of series:
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39
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Identical expressions
- 15x-3y= thirty-nine
- 15x minus 3y equally 39
- 15x minus 3y equally thirty minus nine
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Similar expressions
- 3(9/14):2(1/7)=x:1(1/2)
- 15x+3y=39
- 15*x-3*y=9
15x-3y=39 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Looking for similar summands in the left part:
Move the summands with the other variables
from left part to right part, we given:
$$15 x = 3 y + 39$$
Divide both parts of the equation by 15
We get the answer: x = 13/5 + y/5
15*x-3*y = 39
Looking for similar summands in the left part:
-3*y + 15*x = 39
Move the summands with the other variables
from left part to right part, we given:
$$15 x = 3 y + 39$$
Divide both parts of the equation by 15
x = 39 + 3*y / (15)
We get the answer: x = 13/5 + y/5
The graph
Rapid solution
[src]
13 re(y) I*im(y)
x1 = -- + ----- + -------
5 5 5
$$x_{1} = \frac{\operatorname{re}{\left(y\right)}}{5} + \frac{i \operatorname{im}{\left(y\right)}}{5} + \frac{13}{5}$$
x1 = re(y)/5 + i*im(y)/5 + 13/5
Sum and product of roots
[src]
sum
13 re(y) I*im(y) -- + ----- + ------- 5 5 5
$$\frac{\operatorname{re}{\left(y\right)}}{5} + \frac{i \operatorname{im}{\left(y\right)}}{5} + \frac{13}{5}$$
=
13 re(y) I*im(y) -- + ----- + ------- 5 5 5
$$\frac{\operatorname{re}{\left(y\right)}}{5} + \frac{i \operatorname{im}{\left(y\right)}}{5} + \frac{13}{5}$$
product
13 re(y) I*im(y) -- + ----- + ------- 5 5 5
$$\frac{\operatorname{re}{\left(y\right)}}{5} + \frac{i \operatorname{im}{\left(y\right)}}{5} + \frac{13}{5}$$
=
13 re(y) I*im(y) -- + ----- + ------- 5 5 5
$$\frac{\operatorname{re}{\left(y\right)}}{5} + \frac{i \operatorname{im}{\left(y\right)}}{5} + \frac{13}{5}$$
13/5 + re(y)/5 + i*im(y)/5