Move right part of the equation to
left part with negative sign.
The equation is transformed from
$$169 - x^{2} = \left(x^{2} - 15\right) + 196$$
to
$$\left(169 - x^{2}\right) + \left(\left(15 - x^{2}\right) - 196\right) = 0$$
This equation is of the form
a*x^2 + b*x + c = 0
A quadratic equation can be solved
using the discriminant.
The roots of the quadratic equation:
$$x_{1} = \frac{\sqrt{D} - b}{2 a}$$
$$x_{2} = \frac{- \sqrt{D} - b}{2 a}$$
where D = b^2 - 4*a*c - it is the discriminant.
Because
$$a = -2$$
$$b = 0$$
$$c = -12$$
, then
D = b^2 - 4 * a * c =
(0)^2 - 4 * (-2) * (-12) = -96
Because D<0, then the equation
has no real roots,
but complex roots is exists.
x1 = (-b + sqrt(D)) / (2*a)
x2 = (-b - sqrt(D)) / (2*a)
or
$$x_{1} = - \sqrt{6} i$$
$$x_{2} = \sqrt{6} i$$