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A simplest differential equations of 1order StepbyStep
How to use it?
Differential equation
:
Equation y'=y+sin(x/e)
Equation y"=x+sinx
Equation y''''3y'''+3y''y'=x3
Equation y2*y'+y''=e^x*x^2
Identical expressions
sec^2xtgydxsec^2ytgxdy= zero
sec squared xtgydx minus sec squared ytgxdy equally 0
sec squared xtgydx minus sec squared ytgxdy equally zero
sec2xtgydxsec2ytgxdy=0
sec²xtgydxsec²ytgxdy=0
sec to the power of 2xtgydxsec to the power of 2ytgxdy=0
sec^2xtgydxsec^2ytgxdy=O
Similar expressions
sec^2xtgydx+sec^2ytgxdy=0
Differential equations
/
sec^2xtgydxsec^2ytgxdy=0
Differential equation sec^2xtgydxsec^2ytgxdy=0
+ equation
Solve the differential equation!
⚟
For Cauchy problem:
y(
) =
y'(
) =
y''(
) =
y'''(
) =
y''''(
) =
The graph:
from
to
⌨
y
'
x
dx
dy
0
1
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(
)
pi
i
e
=
+

*
^
/
.
sin
cos
tan
ctan
log
exp
sqrt
cbrt
asin
acos
atan
sinh
cosh
tanh
actan
ctanh
asinh
acosh
atanh
actanh
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