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A simplest differential equations of 1order StepbyStep
How to use it?
Differential equation
:
Equation 2*y'=3+6*y/x+y^2/x^2
Equation y2*y'+y''=e^x/(x^2+1)
Equation p*y'+q*y+y''=0
Equation x^2*y'=(x+y)*y
Identical expressions
sec^ two (x)×tg(y)dy+sec^ two (y)tg(x)dy= zero
sec squared (x)×tg(y)dy plus sec squared (y)tg(x)dy equally 0
sec to the power of two (x)×tg(y)dy plus sec to the power of two (y)tg(x)dy equally zero
sec2(x)×tg(y)dy+sec2(y)tg(x)dy=0
sec2x×tgydy+sec2ytgxdy=0
sec²(x)×tg(y)dy+sec²(y)tg(x)dy=0
sec to the power of 2(x)×tg(y)dy+sec to the power of 2(y)tg(x)dy=0
sec^2x×tgydy+sec^2ytgxdy=0
sec^2(x)×tg(y)dy+sec^2(y)tg(x)dy=O
Similar expressions
sec^2(x)×tg(y)dysec^2(y)tg(x)dy=0
Differential equations
/
sec^2(x)×tg(y)dy+sec^2(y)tg(x)dy=0
Differential equation sec^2(x)×tg(y)dy+sec^2(y)tg(x)dy=0
The teacher will be very surprised to see your correct solution 😉
+ equation
Solve the differential equation!
v
For Cauchy problem:
y(
) =
y'(
) =
y''(
) =
y'''(
) =
y''''(
) =
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