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A simplest differential equations of 1-order Step-by-Step
How to use it?
Differential equation
:
Equation y'=2*y/x
Equation x^2*y''-4*x*y'+6*y=0
Equation y"-6y'+8y=0
Equation (1+e^x)yy’=e^x
Identical expressions
sec^ two (x)*ctg(y)dx+sec^ two (y)*tg(x)dy= zero
sec squared (x) multiply by ctg(y)dx plus sec squared (y) multiply by tg(x)dy equally 0
sec to the power of two (x) multiply by ctg(y)dx plus sec to the power of two (y) multiply by tg(x)dy equally zero
sec2(x)*ctg(y)dx+sec2(y)*tg(x)dy=0
sec2x*ctgydx+sec2y*tgxdy=0
sec²(x)*ctg(y)dx+sec²(y)*tg(x)dy=0
sec to the power of 2(x)*ctg(y)dx+sec to the power of 2(y)*tg(x)dy=0
sec^2(x)ctg(y)dx+sec^2(y)tg(x)dy=0
sec2(x)ctg(y)dx+sec2(y)tg(x)dy=0
sec2xctgydx+sec2ytgxdy=0
sec^2xctgydx+sec^2ytgxdy=0
sec^2(x)*ctg(y)dx+sec^2(y)*tg(x)dy=O
Similar expressions
sec^2(x)*ctg(y)dx-sec^2(y)*tg(x)dy=0
Differential equations
/
sec^2(x)*ctg(y)dx+sec^2(y)*tg(x)dy=0
Differential equation sec^2(x)*ctg(y)dx+sec^2(y)*tg(x)dy=0
The teacher will be very surprised to see your correct solution 😉
+ equation
Solve the differential equation!
v
For Cauchy problem:
y(
) =
y'(
) =
y''(
) =
y'''(
) =
y''''(
) =
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