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How to use it?
Differential equation
:
Equation dy/dx=ycosx/1+2y^2
Equation y''+4y'+3y=e^x
Equation y''y'2y=4x
Equation y’’7y’+6y=sinx
Derivative of
:
dy/dx
Identical expressions
dy/dx=ycosx/ one + two y^2
dy divide by dx equally y co sinus of e of x divide by 1 plus 2y squared
dy divide by dx equally y co sinus of e of x divide by one plus two y squared
dy/dx=ycosx/1+2y2
dy/dx=ycosx/1+2y²
dy/dx=ycosx/1+2y to the power of 2
dy divide by dx=ycosx divide by 1+2y^2
Similar expressions
dy/dx=ycosx/12y^2
Differential equations
/
dy/dx=ycosx/1+2y^2
Differential equation dy/dx=ycosx/1+2y^2
The teacher will be very surprised to see your correct solution 😉
+ equation
Solve the differential equation!
v
For Cauchy problem:
y(
) =
y'(
) =
y''(
) =
y'''(
) =
y''''(
) =
The graph:
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