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  • How to use it?

  • Differential equation:
  • Equation (1+y^2)dx=(1+x^2)dy
  • Equation y'''=cos5x
  • Equation ydy+xdx=0
  • Equation dy=xydx
  • Derivative of:
  • dy/dx dy/dx
  • Identical expressions

  • dy/dx=((x^ four)+(three x^ two)(y^ two)+(y^ four))/(x^ three)(y^3)
  • dy divide by dx equally ((x to the power of 4) plus (3x squared )(y squared ) plus (y to the power of 4)) divide by (x cubed )(y cubed )
  • dy divide by dx equally ((x to the power of four) plus (three x to the power of two)(y to the power of two) plus (y to the power of four)) divide by (x to the power of three)(y cubed )
  • dy/dx=((x4)+(3x2)(y2)+(y4))/(x3)(y3)
  • dy/dx=x4+3x2y2+y4/x3y3
  • dy/dx=((x⁴)+(3x²)(y²)+(y⁴))/(x³)(y³)
  • dy/dx=((x to the power of 4)+(3x to the power of 2)(y to the power of 2)+(y to the power of 4))/(x to the power of 3)(y to the power of 3)
  • dy/dx=x^4+3x^2y^2+y^4/x^3y^3
  • dy divide by dx=((x^4)+(3x^2)(y^2)+(y^4)) divide by (x^3)(y^3)
  • Similar expressions

  • dy/dx=((x^4)+(3x^2)(y^2)-(y^4))/(x^3)(y^3)
  • dy/dx=((x^4)-(3x^2)(y^2)+(y^4))/(x^3)(y^3)

Differential equation dy/dx=((x^4)+(3x^2)(y^2)+(y^4))/(x^3)(y^3)

The teacher will be very surprised to see your correct solution 😉

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For Cauchy problem:

y() =
y'() =
y''() =
y'''() =
y''''() =

The graph:

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