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Linear homogeneous differential equations of 2nd order Step-By-Step
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Differential equations with separable variables Step-by-Step
A simplest differential equations of 1-order Step-by-Step
How to use it?
Differential equation
:
Equation x*y''-xy'+y=0
Equation 4*dx*x-3*dy*y=-2*dx*x*y^2+3*dy*x^2*y
Equation y''+4y=sen(2x)+x
Equation dx*(x*y^2+x)+dy*(x^2*y-y)=0
Identical expressions
dx*(y^ two + two *x*y)-dy*(x^ two)= zero
dx multiply by (y squared plus 2 multiply by x multiply by y) minus dy multiply by (x squared ) equally 0
dx multiply by (y to the power of two plus two multiply by x multiply by y) minus dy multiply by (x to the power of two) equally zero
dx*(y2+2*x*y)-dy*(x2)=0
dx*y2+2*x*y-dy*x2=0
dx*(y²+2*x*y)-dy*(x²)=0
dx*(y to the power of 2+2*x*y)-dy*(x to the power of 2)=0
dx(y^2+2xy)-dy(x^2)=0
dx(y2+2xy)-dy(x2)=0
dxy2+2xy-dyx2=0
dxy^2+2xy-dyx^2=0
dx*(y^2+2*x*y)-dy*(x^2)=O
Similar expressions
dx*(y^2+2*x*y)+dy*(x^2)=0
dx*(y^2-2*x*y)-dy*(x^2)=0
Differential equations
/
dx*(y^2+2*x*y)-dy*(x^2)=0
Differential equation dx*(y^2+2*x*y)-dy*(x^2)=0
The teacher will be very surprised to see your correct solution 😉
+ equation
Solve the differential equation!
v
For Cauchy problem:
y(
) =
y'(
) =
y''(
) =
y'''(
) =
y''''(
) =
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