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y=(x^2-2x+3)e^x

Derivative of y=(x^2-2x+3)e^x

Function f() - derivative -N order at the point
v

The graph:

from to

Piecewise:

The solution

You have entered [src]
/ 2          \  x
\x  - 2*x + 3/*e 
$$\left(x^{2} - 2 x + 3\right) e^{x}$$
d // 2          \  x\
--\\x  - 2*x + 3/*e /
dx                   
$$\frac{d}{d x} \left(x^{2} - 2 x + 3\right) e^{x}$$
Detail solution
  1. Apply the product rule:

    ; to find :

    1. Differentiate term by term:

      1. Apply the power rule: goes to

      2. The derivative of a constant times a function is the constant times the derivative of the function.

        1. The derivative of a constant times a function is the constant times the derivative of the function.

          1. Apply the power rule: goes to

          So, the result is:

        So, the result is:

      3. The derivative of the constant is zero.

      The result is:

    ; to find :

    1. The derivative of is itself.

    The result is:

  2. Now simplify:


The answer is:

The graph
The first derivative [src]
            x   / 2          \  x
(-2 + 2*x)*e  + \x  - 2*x + 3/*e 
$$\left(2 x - 2\right) e^{x} + \left(x^{2} - 2 x + 3\right) e^{x}$$
The second derivative [src]
/     2      \  x
\1 + x  + 2*x/*e 
$$\left(x^{2} + 2 x + 1\right) e^{x}$$
The third derivative [src]
/     2      \  x
\3 + x  + 4*x/*e 
$$\left(x^{2} + 4 x + 3\right) e^{x}$$
The graph
Derivative of y=(x^2-2x+3)e^x