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Derivative of (3x^2)*cos4x

Function f() - derivative -N order at the point
v

The graph:

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Piecewise:

The solution

You have entered [src]
   2         
3*x *cos(4*x)
$$3 x^{2} \cos{\left(4 x \right)}$$
(3*x^2)*cos(4*x)
Detail solution
  1. Apply the product rule:

    ; to find :

    1. The derivative of a constant times a function is the constant times the derivative of the function.

      1. Apply the power rule: goes to

      So, the result is:

    ; to find :

    1. Let .

    2. The derivative of cosine is negative sine:

    3. Then, apply the chain rule. Multiply by :

      1. The derivative of a constant times a function is the constant times the derivative of the function.

        1. Apply the power rule: goes to

        So, the result is:

      The result of the chain rule is:

    The result is:

  2. Now simplify:


The answer is:

The graph
The first derivative [src]
      2                        
- 12*x *sin(4*x) + 6*x*cos(4*x)
$$- 12 x^{2} \sin{\left(4 x \right)} + 6 x \cos{\left(4 x \right)}$$
The second derivative [src]
  /                   2                    \
6*\-8*x*sin(4*x) - 8*x *cos(4*x) + cos(4*x)/
$$6 \left(- 8 x^{2} \cos{\left(4 x \right)} - 8 x \sin{\left(4 x \right)} + \cos{\left(4 x \right)}\right)$$
The third derivative [src]
   /                                 2         \
24*\-3*sin(4*x) - 12*x*cos(4*x) + 8*x *sin(4*x)/
$$24 \left(8 x^{2} \sin{\left(4 x \right)} - 12 x \cos{\left(4 x \right)} - 3 \sin{\left(4 x \right)}\right)$$