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(x^2+(9*y^2)/4+z^2-1)^3-(x^2)*(z^3)-(9*(y^2)*(z^3))/80=0 canonical form

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                     3                      
/                  2\               2  3    
|      2    2   9*y |     2  3   9*y *z     
|-1 + x  + z  + ----|  - x *z  - ------- = 0
\                4  /               80      
$$- x^{2} z^{3} - \frac{9 y^{2} z^{3}}{80} + \left(x^{2} + \frac{9 y^{2}}{4} + z^{2} - 1\right)^{3} = 0$$
-x^2*z^3 - 9*y^2*z^3/80 + (x^2 + 9*y^2/4 + z^2 - 1)^3 = 0
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